document.write( "Question 230798: Hi,
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document.write( "I have a \"Trig Identity\" problem that I'm to verify. I know they are equal by substituting in a value, but I don't know how to approach it. I thought using a conjugate was the way, but it got me nowhere. Here is the problem:\r
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document.write( "(cotX * cosX)/(cotX + cosX) = (cotX - cosX)/(cotX * cosX)\r
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document.write( "Thank you,
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document.write( "Lynn \n" );
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Algebra.Com's Answer #170933 by Alan3354(69443) You can put this solution on YOUR website! (cotX * cosX)/(cotX + cosX) = (cotX - cosX)/(cotX * cosX) \n" ); document.write( "--------- \n" ); document.write( "Since it's all x I'll leave it out. \n" ); document.write( "Cross multiply \n" ); document.write( "(cot*cos)^2 = cot^2 - cos^2 \n" ); document.write( "(cos^2/sin^2)*cos^2 = (cos^2/sin^2) - cos^2 \n" ); document.write( "Divide out cos^2 \n" ); document.write( "cos^2/sin^2 = (1/sin^2) - 1 \n" ); document.write( "cos^2/sin^2 = (1 - sin^2)/sin^2 \n" ); document.write( "cos^2/sin^2 = cos^2/sin^2 \n" ); document.write( "--------------------------- \n" ); document.write( "PS If you sub a value and it doesn't work, you know it's not an identity. \n" ); document.write( "If a value does work, that doesn't guarantee it works for all values. \n" ); document.write( " \n" ); document.write( " |