document.write( "Question 230629: John is twice as old as his brother. Four years ago, he was four times as old as his brother. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #170929 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let j = John's present age \n" ); document.write( "Let b = brother's age now \n" ); document.write( ": \n" ); document.write( "John is twice as old as his brother. \n" ); document.write( "j = 2b \n" ); document.write( "; \n" ); document.write( " Four years ago, he was four times as old as his brother. \n" ); document.write( "j - 4 = 4(b - 4) \n" ); document.write( "j - 4 = 4b - 16 \n" ); document.write( "j = 4b - 16 + 4 \n" ); document.write( "j = 4b - 12 \n" ); document.write( ": \n" ); document.write( " Find their present ages. \n" ); document.write( "Replace j with 2b in the above equation \n" ); document.write( "2b = 4b - 12 \n" ); document.write( "12 = 4b - 2b \n" ); document.write( "12 = 2b \n" ); document.write( "b = 6 yrs is bro \n" ); document.write( ": \n" ); document.write( "obviously, John is 12, \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Prove this in the statement: \n" ); document.write( "\"Four years ago, he was four times as old as his brother. \" \n" ); document.write( "12 - 4 = 4(6 - 4) \n" ); document.write( "8 = 4(2) \n" ); document.write( " |