document.write( "Question 230802: Mr. smith invested $24,000, part at 6% and the rest at 10%. if the interest earned was $2,000, find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #170924 by checkley77(12844)\"\" \"About 
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.10x+.06(24,000-x)=2,000
\n" ); document.write( ".10x+1,440-.06x=2,000
\n" ); document.write( ".04x=2,000-1,440
\n" ); document.write( ".04x=560
\n" ); document.write( "x=560/.04
\n" ); document.write( "x=14,000 invested @ 10%.
\n" ); document.write( "24,000-14,000=10,000 invested @ 6%.
\n" ); document.write( "Proof:
\n" ); document.write( ".10*14,000+.06*10,000=2,000
\n" ); document.write( "1,400+600=2,000
\n" ); document.write( "2,000=2,000
\n" ); document.write( "
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