document.write( "Question 230802: Mr. smith invested $24,000, part at 6% and the rest at 10%. if the interest earned was $2,000, find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #170924 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .10x+.06(24,000-x)=2,000 \n" ); document.write( ".10x+1,440-.06x=2,000 \n" ); document.write( ".04x=2,000-1,440 \n" ); document.write( ".04x=560 \n" ); document.write( "x=560/.04 \n" ); document.write( "x=14,000 invested @ 10%. \n" ); document.write( "24,000-14,000=10,000 invested @ 6%. \n" ); document.write( "Proof: \n" ); document.write( ".10*14,000+.06*10,000=2,000 \n" ); document.write( "1,400+600=2,000 \n" ); document.write( "2,000=2,000 \n" ); document.write( " |