document.write( "Question 30385: (1/a + 1) / (1/a2 - 1)\r
\n" ); document.write( "\n" ); document.write( "The book gives an answer as: a/1-a, but I just can't see how they get it.\r
\n" ); document.write( "\n" ); document.write( "You must first multiply both numerator and denominator by the LCD, right? Isn't this 2a? When I multiply both by it, I get:\r
\n" ); document.write( "\n" ); document.write( "(2 + 2a) / (1 - 2a)\r
\n" ); document.write( "\n" ); document.write( "and get stuck there. What am I doing wrong?
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Algebra.Com's Answer #17092 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
Assuming you mean: \"+%28+1%2F%28a%2B1%29+%29+%2F+%28+1%2F%28a%5E2-1%29+%29+\", we get:
\n" ); document.write( "\"+%28+1%2F%28a%2B1%29+%29+%2A+%28+%28a%5E2-1%29%2F1+%29+\"
\n" ); document.write( "\"+%28a%5E2-1%29%2F%28a%2B1%29+\"
\n" ); document.write( "\"+%28%28a-1%29%28a%2B1%29%29%2F%28a%2B1%29+\"
\n" ); document.write( "\"+%28a-1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "As for the answer you quote, a/(a-1), I cannot see how that was gotten, from the starting point i used.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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