document.write( "Question 230666: The denominator of a certain fraction is three times the numerator. If 2 is added to the numerator and subtracted from the denominator, the resulting fraction is equivalent to 1. What was the original fraction (not written in lowest terms)? \n" ); document.write( "
Algebra.Com's Answer #170902 by unlockmath(1688)\"\" \"About 
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Hello, \r
\n" ); document.write( "\n" ); document.write( "Let's first write out how the fraction will look:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " x + 2/3x-2 = 1 \r
\n" ); document.write( "\n" ); document.write( "Now all we have to do is solve what x equals. \r
\n" ); document.write( "\n" ); document.write( "First we multiply both sides by 3x-2\r
\n" ); document.write( "\n" ); document.write( "This will then make the equation look like this:\r
\n" ); document.write( "\n" ); document.write( " x + 2 = 3x - 2\r
\n" ); document.write( "\n" ); document.write( "Now subtract 2 from both sides and this leaves\r
\n" ); document.write( "\n" ); document.write( " x = 3x - 4\r
\n" ); document.write( "\n" ); document.write( "Now subtract 3x from both sides and this will give you:\r
\n" ); document.write( "\n" ); document.write( " -2x = -4\r
\n" ); document.write( "\n" ); document.write( "Now divide both sides by -2 and this gives you \r
\n" ); document.write( "\n" ); document.write( " x = 2\r
\n" ); document.write( "\n" ); document.write( "plugging 2 into the original formula gives you:\r
\n" ); document.write( "\n" ); document.write( " 2 + 2/3 times 2-2 = 1 this turns into: \r
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\n" ); document.write( "\n" ); document.write( " 4/4=1
\n" ); document.write( "You're welcome,
\n" ); document.write( "RJ Toftness
\n" ); document.write( "www.math-unlock.com
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