document.write( "Question 3869: Sorry Jon!\r
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document.write( "It is
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document.write( "x + 7y = -39
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document.write( "-3x - 2y = 22\r
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document.write( "Substitution method ,I can't get it to work out. \n" );
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Algebra.Com's Answer #1709 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! let 2 eqns be eqn1 and eqn2, respectively.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in eqn1, x = -39 - 7y. So put this (ie substitute it) into the second eqn, which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3(-39-7y) - 2y = 22 --> expand the bracket and simply it all: \n" ); document.write( "117+21y - 2y = 22 \n" ); document.write( "19y = 22-117 \n" ); document.write( "19y = -95 \n" ); document.write( "y = -95/19 \n" ); document.write( "y = -5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So now put this into either eqn1 or eqn2..pick the easiest looking one!... eqn2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This becomes -3x -2(-5) = 22 \n" ); document.write( "-3x + 10 = 22 \n" ); document.write( "-3x = 22-10 \n" ); document.write( "-3x = 12 \n" ); document.write( "x = -12/3 \n" ); document.write( "x = -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now but both answers into the other eqn and see if you do get -39. If you do, you KNOW the answer is correct!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4 + 7(-5) \n" ); document.write( "-4 - 35 \n" ); document.write( "-39 --> CORRECT!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |