document.write( "Question 230649: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kg's of each are needed to make a 3kg box that costs $15.00 ? \n" ); document.write( "
Algebra.Com's Answer #170894 by checkley77(12844)\"\" \"About 
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6x+4(3-x)=15
\n" ); document.write( "6x+12-4x=15
\n" ); document.write( "2x=15-12
\n" ); document.write( "2x=3
\n" ); document.write( "x=3/2
\n" ); document.write( "x=1.5 kg of the $6 candy is used.
\n" ); document.write( "3=1.5=1.5 kg of the $4 candy is used.
\n" ); document.write( "Proof:
\n" ); document.write( "6*1.5+4*1.5=15
\n" ); document.write( "9+6=15
\n" ); document.write( "15=15
\n" ); document.write( "
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