document.write( "Question 230704: can you help me with this:\r
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document.write( "2 legs of a right triangle have a total length of 21cm. hypotenuse is 15cm. Find the length of each leg of this right triangle. \n" );
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Algebra.Com's Answer #170876 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=21 OR X=21-Y \n" ); document.write( "X^2+Y^2=15^2 \n" ); document.write( "REPLACE THE X TERM IN THE SECOND EQUATION WITH (21-Y) & SOLVE FOR Y. \n" ); document.write( "(21-Y)^2+Y^2=15^2 \n" ); document.write( "441-42Y+Y^2+Y^2=225 \n" ); document.write( "2Y^2-42Y+441-225=0 \n" ); document.write( "2Y^2-42Y+216=0 \n" ); document.write( "2(Y^2-21Y+108)=0 \n" ); document.write( "2(Y-12)(Y-9)=0 \n" ); document.write( "Y-12=0 \n" ); document.write( "Y=12 ANS. X=9 ANS. \n" ); document.write( "Y-9=0 \n" ); document.write( "Y=9 ANS. X=12 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "9^2+12^2=15^2 \n" ); document.write( "81+144=225 \n" ); document.write( "225=225\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |