document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230699>Question 230699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2/9)-1 The minus 1 is on the outside of the parenthesis, and the 2/9 is a fraction. It says to solve without an exponent and i need help please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170855 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, <BR>\n" );
document.write( "I hope I understand the problem correctly. <BR>\n" );
document.write( "I take it that the -1 is the power of the fraction 2/9.\r<BR>\n" );
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document.write( "So the get rid of the -1 power you move the fraction 2/9 to the denominator<BR>\n" );
document.write( "like this:\r<BR>\n" );
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document.write( "        1/ 2/9 to the first power. the negative -1 turns to positive 1\r<BR>\n" );
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document.write( "This can be further simplified since 1 over the fraction 2/9 can be rewritten as <BR>\n" );
document.write( " 9/2 or  reduced further to  4 1/2. \r<BR>\n" );
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document.write( "Hopes this help. \r<BR>\n" );
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document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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