document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230504>Question 230504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, how would i solve the absoulte value of -9+v over 8= 3? I thought i would make v=72, then i thought i would use the common denominator of 8, but the answer is coming our correctly. Please explain because I have other problems like this one. Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170760 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you mean:<BR>\n" );
document.write( "|(-9+v)/8|=3<BR>\n" );
document.write( "Then:<BR>\n" );
document.write( "(-9+v)=24<BR>\n" );
document.write( "v=24+9<BR>\n" );
document.write( "v=33 ans.<BR>\n" );
document.write( "|(-9+v)/8|=-3<BR>\n" );
document.write( "(-9+v)/8=-3<BR>\n" );
document.write( "-9+v=-24<BR>\n" );
document.write( "v=-24+9<BR>\n" );
document.write( "v=-15 ans.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "If you mean:<BR>\n" );
document.write( "|-9+v/8|=3 <BR>\n" );
document.write( "Then.<BR>\n" );
document.write( "v/8=3+9<BR>\n" );
document.write( "v/8=12<BR>\n" );
document.write( "v=96 ans.<BR>\n" );
document.write( "|-9+v/8|=-3 <BR>\n" );
document.write( "v/8=-3+9<BR>\n" );
document.write( "v/8=6<BR>\n" );
document.write( "v=48 ans. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );