document.write( "Question 230578: the length of a rectangle is 9 in.greater than the width. The area is 36 in.2 \r
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\n" ); document.write( "\n" ); document.write( "Find the dimensions.
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Algebra.Com's Answer #170738 by checkley77(12844)\"\" \"About 
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L=W+9
\n" ); document.write( "LW=36
\n" ); document.write( "(W+90)W=36
\n" ); document.write( "W^2+9W-36=0
\n" ); document.write( "(W+12)(W-3)=0
\n" ); document.write( "W-3=0
\n" ); document.write( "W=3 ANS. FOR THE WIDTH.
\n" ); document.write( "L=3+9
\n" ); document.write( "L=12 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*12=36
\n" ); document.write( "36=36
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