document.write( "Question 230578: the length of a rectangle is 9 in.greater than the width. The area is 36 in.2 \r
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document.write( "Find the dimensions. \n" );
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Algebra.Com's Answer #170738 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+9 \n" ); document.write( "LW=36 \n" ); document.write( "(W+90)W=36 \n" ); document.write( "W^2+9W-36=0 \n" ); document.write( "(W+12)(W-3)=0 \n" ); document.write( "W-3=0 \n" ); document.write( "W=3 ANS. FOR THE WIDTH. \n" ); document.write( "L=3+9 \n" ); document.write( "L=12 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "3*12=36 \n" ); document.write( "36=36 \n" ); document.write( " |