document.write( "Question 230556: Jason's bank account contains 30 coins(all nickles or dimes). He has four times as many nickels as dimes. How much money does he have? \n" ); document.write( "

Algebra.Com's Answer #170734 by algebrapro18(249) $\"\"$ $\"About$

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Well first lets assign varables. Let n be the number of nickles and d be the number of dimes. Then from the problem we get the following system of equations:
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\n" ); document.write( "\n" ); document.write( "n+d=30
\n" ); document.write( "4d=n
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\n" ); document.write( "\n" ); document.write( "now since n is already solved for in the second equation then we can just substitute that into the first equation and solve for d.
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\n" ); document.write( "\n" ); document.write( "n+d=30
\n" ); document.write( "4d+d=30
\n" ); document.write( "d = 6
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\n" ); document.write( "\n" ); document.write( "now we can substitute that back into the second equation and find n.
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\n" ); document.write( "\n" ); document.write( "4d=n
\n" ); document.write( "4(6)=n
\n" ); document.write( "24=n
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\n" ); document.write( "\n" ); document.write( "so we know that Jason has 24 nickles and 6 dimes for a total of $0.6+$1.20 = $1.80. \n" ); document.write( "

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