document.write( "Question 230532: Please help me solve this one, thanks in advance.\r
\n" ); document.write( "\n" ); document.write( "x^2/3-x^1/3-20=0
\n" ); document.write( "

Algebra.Com's Answer #170727 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
The key to the simple solution for this equation is to recognize that \"x%5E%282%2F3%29+=+%28x%5E%281%2F3%29%29%5E2\". Once we see this, we can recognize that your equation is a quadratic equation in \"x%5E%281%2F3%29\" and that this quadratic equation will factor fairly easily:
\n" ); document.write( "\"%28x%5E%281%2F3%29+-+5%29%28x%5E%281%2F3%29+%2B+4%29+=+0\"
\n" ); document.write( "(If, after thinking about this, you still have trouble seeing this, see below for a way to solve this that is longer but may be clearer.)
\n" ); document.write( "By the Zero Product Property we know that this product is zero only if one of the factors is zero. So:
\n" ); document.write( "\"x%5E%281%2F3%29+-+5+=+0\" or \"x%5E%281%2F3%29+%2B+4+=+0\"
\n" ); document.write( "Solving these we get:
\n" ); document.write( "\"x%5E%281%2F3%29+=+5\" or \"x%5E%281%2F3%29+=+-4\"
\n" ); document.write( "Cubing both sides:
\n" ); document.write( "\"x+=+125\" or \"x+=+-64\"

\n" ); document.write( "A longer, perhaps clearer, solution. We still will be using \"x%5E%282%2F3%29+=+x%5E%281%2F3%29%5E2\". But this time we will use a temporary variable to make things clearer.
\n" ); document.write( "Let \"q+=+x%5E%281%2F3%29\"
\n" ); document.write( "then \"q%5E2+=+%28x%5E%281%2F3%29%29%5E2+=+x%5E%282%2F3%29\"
\n" ); document.write( "Now we'll substitute these into your equation:
\n" ); document.write( "\"q%5E2+-+q+-+20+=+0\"
\n" ); document.write( "This is clearly a quadratic equation and the factoring is more obvious:
\n" ); document.write( "\"%28q-5%29%28q%2B4%29=0\"
\n" ); document.write( "Solving this we get:
\n" ); document.write( "\"q-5+=+0\" or \"q%2B4=0\"
\n" ); document.write( "\"q+=+5\" or \"q+=+-4\"
\n" ); document.write( "At this point we have solved for q. But we want to solve for x. So we substitute back in for q:
\n" ); document.write( "\"x%5E%281%2F3%29+=+5\" or \"x%5E%281%2F3%29+=+-4\"
\n" ); document.write( "To solve for x we cube both sides of this:
\n" ); document.write( "\"x+=+125\" or \"x+=+-64\"

\n" ); document.write( "If you have to use the temporary variables to solve problems like this, it would be good, after a while, to wean yourself off the temporary variables.
\n" ); document.write( "
\n" ); document.write( "
\n" );