document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230566>Question 230566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tell whether the line for each pair of equations are parallel,perpendicular,or neither.<BR>\n" );
document.write( "y=-1/2x-11 16x-8y=-8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170726 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Easiest way is to convert both equations to slope-intercept form of y = mx + b where m is the slope and b is the y-intercept.\r<BR>\n" );
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document.write( "First equation is:\r<BR>\n" );
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document.write( "y = -(1/2)x - 11\r<BR>\n" );
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document.write( "It is already in slope intercept form.\r<BR>\n" );
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document.write( "Second equation is\r<BR>\n" );
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document.write( "16x - 8y = -8<BR>\n" );
document.write( "subtract 16x from both sides of the equation to get:<BR>\n" );
document.write( "-8y = -16x - 8<BR>\n" );
document.write( "divide both sides of the eqution by -8 to get:<BR>\n" );
document.write( "y = 2x + 1\r<BR>\n" );
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document.write( "If the slopes are equal they would be either identical or parallel to each other.<BR>\n" );
document.write( "If the slopes are negative reciprocals of each other, they would be perpendicular to each other.\r<BR>\n" );
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document.write( "They are not identical or parallel to each other.\r<BR>\n" );
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document.write( "Take negative reciprocal of (-1/2) to get 2.\r<BR>\n" );
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document.write( "Slopes are negative reciprocals of each other so these line should be identical.\r<BR>\n" );
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document.write( "Prove by graphing.\r<BR>\n" );
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