document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230148>Question 230148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please prove: 1-cosx/1+cosx=(cscx-cotx)squared </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170716 by </B><A HREF=/tutors/aboutme.mpl?userid=chibisan><B>chibisan(131)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chibisan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chibisan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets rationalize by multiplying the denominator and numerator by 1-cosx\r<BR>\n" );
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document.write( "(1-cosx)^2 / (1-cos^2x)<BR>\n" );
document.write( "1-2cosx+cos^2x / sin^2x\r<BR>\n" );
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document.write( "1/sin^2x -2cosx/sin^2x + cos^2x/sin^2x<BR>\n" );
document.write( "cosec^2x -2cosx/sin^2x + cot^2x<BR>\n" );
document.write( "(cosecx-cotx)^2(proven) <BR>\n" );
document.write( "[ by using a^2 - 2ab + b^2 = (a-b)^2 ] </SPAN>\n" );
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