document.write( "Question 230553: Carlos has some pennies, nickels, and quarters in his pocket. He has 2 more nickels than quarters. He has twice as many pennies as nickels. The total value is $1.74. How many of each coin does Carlos have? \n" ); document.write( "
Algebra.Com's Answer #170713 by likaaka(51)\"\" \"About 
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First begin by naming your variables.
\n" ); document.write( "Let P be the amount, not worth, of pennies Carlos has, N will be the amount of nickels, and Q the amount of quarters.
\n" ); document.write( "So if Carlos has 2 more nickels than quarters, your first equation is
\n" ); document.write( "N = Q + 2
\n" ); document.write( "If he has twice as many pennies as nickels, then
\n" ); document.write( "P = 2N
\n" ); document.write( "Now we use the value of each coin to determine the third equation.
\n" ); document.write( "0.01P + 0.05N + 0.25Q = 1.74\r
\n" ); document.write( "\n" ); document.write( "Here's your system of equations
\n" ); document.write( "N = Q + 2
\n" ); document.write( "P = 2N
\n" ); document.write( "0.01P + 0.05N + 0.25Q = 1.74
\n" ); document.write( "I would start be rearranging the first equation so that it's solved for Q
\n" ); document.write( "N = Q + 2 becomes Q = N - 2 by subtracting 2 from both sides\r
\n" ); document.write( "\n" ); document.write( "Now substitute the value of Q and the value of P into the third equation to solve for N
\n" ); document.write( "0.01(2N) + 0.05N + 0.25(N-2) = 1.74, distribute
\n" ); document.write( "0.02N + 0.05N + 0.25N - 0.5 = 1.74, combine like terms
\n" ); document.write( "0.32N - 0.5 = 1.74, add 0.5 to both sides
\n" ); document.write( "0.32N = 2.24, divide both sides by 0.32
\n" ); document.write( "N = 7, so Carlos has 7 nickels\r
\n" ); document.write( "\n" ); document.write( "Given Q = N - 2 and N = 7 solve for Q
\n" ); document.write( "Q = 7 - 2
\n" ); document.write( "Q = 5, so Carlos has 5 quarters\r
\n" ); document.write( "\n" ); document.write( "Given P = 2N and N = 7
\n" ); document.write( "P = 2(7)
\n" ); document.write( "P = 14, so Carlos has 14 pennies\r
\n" ); document.write( "\n" ); document.write( "CHECK:
\n" ); document.write( "0.01(14) + 0.05(7) + 0.25(5) = 1.74
\n" ); document.write( "0.14 + 0.35 + 1.25 = 1.74
\n" ); document.write( "1.74 = 1.74
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