document.write( "Question 230498: The bottom of Jim's rectangular bait box is 3 inches longer than it is wide. The diagonal is 15 inches. What is the area of the bottom of the box? \n" ); document.write( "
Algebra.Com's Answer #170695 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "First you need to find the measurement of of both sides of the rectangle then
\n" ); document.write( "we can find the area. \r
\n" ); document.write( "\n" ); document.write( "Use the formula A^2 + B^2 = C^2\r
\n" ); document.write( "\n" ); document.write( "We know the hypotenuse is 15 inches.\r
\n" ); document.write( "\n" ); document.write( "Let x = one side of the rectangle and x + 3 be the other side. \r
\n" ); document.write( "\n" ); document.write( "Therefore: \r
\n" ); document.write( "\n" ); document.write( "x^2 + (x+3)^2 = 15^2 this works out to\r
\n" ); document.write( "\n" ); document.write( "x^2 + x^2 + 6x + 9 = 225 combine like terms\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 6x + 9 = 225 subtract 225 from both sides\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 6x - 216 = 0 now we can solve x by the quadratic formula\r
\n" ); document.write( "\n" ); document.write( "x = 9\r
\n" ); document.write( "\n" ); document.write( "Therefore one side is 9 inches and the other side is 12 inches.
\n" ); document.write( "Multiply these sides and the answer is:\r
\n" ); document.write( "\n" ); document.write( "108 square inches\r
\n" ); document.write( "\n" ); document.write( "You're welcome
\n" ); document.write( "RJ Toftness
\n" ); document.write( "www.math-unlock.com
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