document.write( "Question 230498: The bottom of Jim's rectangular bait box is 3 inches longer than it is wide. The diagonal is 15 inches. What is the area of the bottom of the box? \n" ); document.write( "
Algebra.Com's Answer #170695 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "First you need to find the measurement of of both sides of the rectangle then \n" ); document.write( "we can find the area. \r \n" ); document.write( "\n" ); document.write( "Use the formula A^2 + B^2 = C^2\r \n" ); document.write( "\n" ); document.write( "We know the hypotenuse is 15 inches.\r \n" ); document.write( "\n" ); document.write( "Let x = one side of the rectangle and x + 3 be the other side. \r \n" ); document.write( "\n" ); document.write( "Therefore: \r \n" ); document.write( "\n" ); document.write( "x^2 + (x+3)^2 = 15^2 this works out to\r \n" ); document.write( "\n" ); document.write( "x^2 + x^2 + 6x + 9 = 225 combine like terms\r \n" ); document.write( "\n" ); document.write( "2x^2 + 6x + 9 = 225 subtract 225 from both sides\r \n" ); document.write( "\n" ); document.write( "2x^2 + 6x - 216 = 0 now we can solve x by the quadratic formula\r \n" ); document.write( "\n" ); document.write( "x = 9\r \n" ); document.write( "\n" ); document.write( "Therefore one side is 9 inches and the other side is 12 inches. \n" ); document.write( "Multiply these sides and the answer is:\r \n" ); document.write( "\n" ); document.write( "108 square inches\r \n" ); document.write( "\n" ); document.write( "You're welcome \n" ); document.write( "RJ Toftness \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |