document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30393>Question 30393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I have a problem I can't figure out.  A litre of cream has 9.2% butterfat.  How much skim milk containing 2% butterfat should be added to the cream to obtain a mixture with 6.4% butterfat.   I'm not sure what to use as the variable.  Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17068 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6.4=9.2x + 2(1-x) or 6.4 = 9.2x + 2 - 2x or 4.4=7.2x or x=4.4/7.2 or x=.6111\r<BR>\n" );
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document.write( "1-.6111=.3889 \r<BR>\n" );
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document.write( "proof: 9.2 x .6111 = 5.62  2 x .3889 = .78  or 5.62+.78=6.4.   </SPAN>\n" );
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