document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230225>Question 230225</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Can you help with this question?<BR>\n" );
document.write( "An athelete whose event is the shot put releases a shot. When the shot whose path is shown by the graph is releases at an angle of 45 degrees, its height, f(x), in feet, can be modeled by f(x)=-0.02x^2+1.0x+6.5, where x is the shots horizontal distance, in feet, from its point of release. \r<BR>\n" );
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document.write( "a.	Where is the maximum height of the shot and how far from the point of release does this occur<BR>\n" );
document.write( "b.	What is the shots maximum horizontal distance to the nearest tenth, of a foot or the distance of the throw.<BR>\n" );
document.write( "c.	From what height was the shot released?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170661 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An athlete whose event is the shot put releases a shot.<BR>\n" );
document.write( " When the shot whose path is shown by the graph is releases at an angle of 45<BR>\n" );
document.write( " degrees, its height, f(x), in feet, can be modeled by f(x)=-0.02x^2+1.0x+6.5,<BR>\n" );
document.write( " where x is the shots horizontal distance, in feet, from its point of release.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-10%2C+60%2C+-10%2C+25%2C+-.02x%5E2%2Bx%2B6.5%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-10%2C+60%2C+-10%2C+25%2C+-.02x%5E2%2Bx%2B6.5%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a. Where is the maximum height of the shot and how far from the point of release does this occur?<BR>\n" );
document.write( "You can see on the graph that max height is about 20 ft and occurs at about 25 ft<BR>\n" );
document.write( "however, you can calculate this: Find the axis of symmetry (x=-b/(2a)<BR>\n" );
document.write( "In this equation a=-.02; b=1<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%2F%282%2A-.02%29 ALIGN=MIDDLE  ALT=\"%28-1%29%2F%282%2A-.02%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%29%2F%28-.04%29 ALIGN=MIDDLE  ALT=\"%28-1%29%2F%28-.04%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +25 is the horizontal distance<BR>\n" );
document.write( "Find the height: substitute 25 for x in the given equation<BR>\n" );
document.write( "h = -0.02(25^2) +1.0(25)+ 6.5<BR>\n" );
document.write( "h = -0.02(625) + (25)+ 6.5<BR>\n" );
document.write( "h = -12.5 + 25 + 6.5<BR>\n" );
document.write( "h = 19 ft is the max height<BR>\n" );
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document.write( "b. What is the shots maximum horizontal distance to the nearest tenth, of a foot or the distance of the throw.<BR>\n" );
document.write( "That occurs when h = 0<BR>\n" );
document.write( ".02x^2 + 1x + 6.5 = 0<BR>\n" );
document.write( "Use the quadratic formula: a=-.02; b=1; c=6.5<BR>\n" );
document.write( "The positive solution: x = 55.8 ft<BR>\n" );
document.write( ";<BR>\n" );
document.write( "c. From what height was the shot released?<BR>\n" );
document.write( "The value of h when x = 0 is 6.5 ft (you can see this on the graph) </SPAN>\n" );
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