document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30435>Question 30435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please explain how to factor the following problem by grouping to solve the equation.  x^3+3x^2-4x-12=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17066 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please explain how to factor the following problem by grouping to solve the equation.<BR>\n" );
document.write( "LET F(X)= x^3+3x^2-4x-12=0<BR>\n" );
document.write( "TRY PUTTING X=0,1,-1,2,-2..ETC..TO GET A ZERO<BR>\n" );
document.write( "WE FIND AT X=2..F(2)=2^3+3*2^2-4*2-12=8+12-8-12=0...SO X-2 IS A FACTOR.DIVIDE F(X) WITH X-2 NOW<BR>\n" );
document.write( "2...|1..........3..........-4.........-12<BR>\n" );
document.write( "....|0..........2..........10..........12<BR>\n" );
document.write( "..................................................<BR>\n" );
document.write( ".....1..........5...........6...........0<BR>\n" );
document.write( "HENCE X^2+5X+6 IS THE QUOTIENT<BR>\n" );
document.write( "=X^2+2X+3X+6=X(X+2)+3(X+2)=(X+2)(X+3)<BR>\n" );
document.write( "HENCE F(X)=(X-2)(X+2)(X+3) </SPAN>\n" );
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