document.write( "Question 230465: The length of the rectangle is 1.5 times its width and the perimeter is 75 feet\r
\n" ); document.write( "\n" ); document.write( "I did guess and check but i couldnt find the answer
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Algebra.Com's Answer #170644 by texttutoring(324)\"\" \"About 
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You have 2 variables (Length and Width). You need to come up with 2 equations.\r
\n" ); document.write( "\n" ); document.write( "the perimeter is 75 feet. A rectangle is composed of 2 lengths and 2 widths.\r
\n" ); document.write( "\n" ); document.write( "Your equations are:\r
\n" ); document.write( "\n" ); document.write( "Eqn 1: 2w+2L=75
\n" ); document.write( "Eqn 2: 1.5w=L\r
\n" ); document.write( "\n" ); document.write( "Substitute Eqn 2 into Eqn 1:\r
\n" ); document.write( "\n" ); document.write( "2w+2(1.5w)=75
\n" ); document.write( "2w+3w=75
\n" ); document.write( "5w=75
\n" ); document.write( "w=15\r
\n" ); document.write( "\n" ); document.write( "Use Eqn 2 to find L:\r
\n" ); document.write( "\n" ); document.write( "1.5w=L
\n" ); document.write( "1.5*15=L
\n" ); document.write( "L=22.5\r
\n" ); document.write( "\n" ); document.write( "The width is 15 feet, the length is 22.5 feet.
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