document.write( "Question 230465: The length of the rectangle is 1.5 times its width and the perimeter is 75 feet\r
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document.write( "I did guess and check but i couldnt find the answer \n" );
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Algebra.Com's Answer #170644 by texttutoring(324)![]() ![]() You can put this solution on YOUR website! You have 2 variables (Length and Width). You need to come up with 2 equations.\r \n" ); document.write( "\n" ); document.write( "the perimeter is 75 feet. A rectangle is composed of 2 lengths and 2 widths.\r \n" ); document.write( "\n" ); document.write( "Your equations are:\r \n" ); document.write( "\n" ); document.write( "Eqn 1: 2w+2L=75 \n" ); document.write( "Eqn 2: 1.5w=L\r \n" ); document.write( "\n" ); document.write( "Substitute Eqn 2 into Eqn 1:\r \n" ); document.write( "\n" ); document.write( "2w+2(1.5w)=75 \n" ); document.write( "2w+3w=75 \n" ); document.write( "5w=75 \n" ); document.write( "w=15\r \n" ); document.write( "\n" ); document.write( "Use Eqn 2 to find L:\r \n" ); document.write( "\n" ); document.write( "1.5w=L \n" ); document.write( "1.5*15=L \n" ); document.write( "L=22.5\r \n" ); document.write( "\n" ); document.write( "The width is 15 feet, the length is 22.5 feet. \n" ); document.write( " |