document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230378>Question 230378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that the largest decreased by 3times the second is 47 less than the smallest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170592 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find three consecutive odd integers such that the largest decreased by 3times the second is 47 less than the smallest.<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "1st: 2x-1<BR>\n" );
document.write( "2nd: 2x+1<BR>\n" );
document.write( "3rd: 2x+3<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "2x+3-3(2x+1) = 2x-1-47<BR>\n" );
document.write( "2x+3-6x-3 = 2x-48<BR>\n" );
document.write( "-6x = -48<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "1st:2*8-1 = 15<BR>\n" );
document.write( "2nd: 17<BR>\n" );
document.write( "3rd: 19<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );