document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230267>Question 230267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hilton university drama club sold 311 tickets for a play. student tickets cost 50 cents each,nonstudent tickets cost $1.50. if total receipts were 385.50, find how many tickets of each type were sold. \r<BR>\n" );
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document.write( "how to set if up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170583 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to have 2 equations with 2 variables.\r<BR>\n" );
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document.write( "Let x=Number of student tickets, y=Number of Non-student tickets\r<BR>\n" );
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document.write( "Equation 1:  x+y=311<BR>\n" );
document.write( "Equation 2:  0.50x + 1.50y = 385.50\r<BR>\n" );
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document.write( "To solve, I will use substitution by isolating for x in equation 1.\r<BR>\n" );
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document.write( "x = 311 - y\r<BR>\n" );
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document.write( "Substitute this into equation 2:\r<BR>\n" );
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document.write( "0.50(311-y) + 1.50y = 385.50<BR>\n" );
document.write( "155.5 - 0.5y + 1.50y = 385.50<BR>\n" );
document.write( "y=385.50 - 155.5<BR>\n" );
document.write( "y=230\r<BR>\n" );
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document.write( "Find x by subbing y=230 into Equation 1:\r<BR>\n" );
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document.write( "x = 311 - 230<BR>\n" );
document.write( "x = 81\r<BR>\n" );
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document.write( "The number of student tickets sold was 81, and non-student tickets was 230. </SPAN>\n" );
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