document.write( "Question 230340: hi i need help with these special factoring problems\r
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document.write( "5+^2-16=-12
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document.write( "x(x-11)=12
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document.write( "(x-6)(x+1)=-10
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document.write( "(2x+5)(x+1)
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document.write( "(a-4)(a+7)=-18 \n" );
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Algebra.Com's Answer #170574 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 5+^2-16=-12 believe you're missing a value preceeding the (^) sign? \n" ); document.write( "--------------------- \n" ); document.write( "x(x-11)=12 \n" ); document.write( "x^2-11x-12=0 \n" ); document.write( "(x-12)(x+1)=0 \n" ); document.write( "x-12=0 \n" ); document.write( "1=12 ans \n" ); document.write( "x+1=0 \n" ); document.write( "x=-1 ans \n" ); document.write( "------------------- \n" ); document.write( "(x-6)(x+1)=-10 \n" ); document.write( "x^2-5x-6+10=0 \n" ); document.write( "x^2-5x+4=0 \n" ); document.write( "(x-4)(x-1)=0 \n" ); document.write( "x-4=0 \n" ); document.write( "x=4 ans \n" ); document.write( "x-1=0 \n" ); document.write( "x=1 ans. \n" ); document.write( "------------------------- \n" ); document.write( "(2x+5)(x+1) is there supposed to be an = sign here? \n" ); document.write( "------------------------------- \n" ); document.write( "(a-4)(a+7)=-18 \n" ); document.write( "a^2-4a+7a-28=-18 \n" ); document.write( "a^2+3a-28+18=0 \n" ); document.write( "a^2+3a-10=0 \n" ); document.write( "(a+5)(a-2)=0 \n" ); document.write( "a+5=0 \n" ); document.write( "a=-5 ans. \n" ); document.write( "a-2=0 \n" ); document.write( "a=2 ans. \n" ); document.write( " |