document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230288>Question 230288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 9-by-12 rectangular picture is framed by a border of uniform width. Given that the combined area of picture plus frame is 180 square units, find the width of the border </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170539 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X BE THE BORDER WIDTH.<BR>\n" );
document.write( "(9+2X)(12+2X)=180<BR>\n" );
document.write( "108+24X+18X+4X^2=180<BR>\n" );
document.write( "4X^2+42X+108-180=0<BR>\n" );
document.write( "4X^2+42-72=0<BR>\n" );
document.write( "(2X-3)(2X+24)=0<BR>\n" );
document.write( "2X=3<BR>\n" );
document.write( "X=3/2<BR>\n" );
document.write( "X=1.5 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(9+2*1.5)(12+2*1.5)=180<BR>\n" );
document.write( "(9+3)(12+3)=180<BR>\n" );
document.write( "12*15=180<BR>\n" );
document.write( "180=180<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );