document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230283>Question 230283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of the supplement of an angle is 60 more than twice the measure of an angle.  Find the measure of the larger angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170512 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The measure of the supplement of an angle is 60 more than twice the measure of an angle.  Find the measure of the larger angle.\r<BR>\n" );
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document.write( "Step 1.  Supplementary angles means two angles add up to 180 degrees.\r<BR>\n" );
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document.write( "Step 2.  Let x be the angle.\r<BR>\n" );
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document.write( "Step 3.  Let 2x be twice the angle\r<BR>\n" );
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document.write( "Step 4.  Let 180-x be the supplementary angle.\r<BR>\n" );
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document.write( "Step 5.  Then 180-x=2x+60 since the supplement of an angle is 60 more than twice the measure of an angle.\r<BR>\n" );
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document.write( "Step 6.  Solving 180-x=2x+60 yields the following steps\r<BR>\n" );
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document.write( "Add x to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-x%2Bx=2x%2B60%2Bx ALIGN=MIDDLE  ALT=\"180-x%2Bx=2x%2B60%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180=3x%2B60 ALIGN=MIDDLE  ALT=\"180=3x%2B60\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Subtract 60 from both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-60=3x%2B60-60 ALIGN=MIDDLE  ALT=\"180-60=3x%2B60-60\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=120=3x ALIGN=MIDDLE  ALT=\"120=3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide by 3 to both sides of the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=120%2F3=3x%2F3 ALIGN=MIDDLE  ALT=\"120%2F3=3x%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=40 ALIGN=MIDDLE  ALT=\"x=40\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-x=140 ALIGN=MIDDLE  ALT=\"180-x=140\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Check equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180-x=2x%2B60 ALIGN=MIDDLE  ALT=\"180-x=2x%2B60\"   DISABLED_style= \"max-width:90%; height:auto;\" > if true...140=2*40+60=140 which is a true statement.\r<BR>\n" );
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document.write( "Step 7.  The larger angle is 140 degrees.\r<BR>\n" );
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document.write( "I hope the above steps were helpful.\r<BR>\n" );
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document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r<BR>\n" );
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document.write( "Good luck in your studies!\r<BR>\n" );
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document.write( "Respectfully,<BR>\n" );
document.write( "Dr J\r<BR>\n" );
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document.write( " </SPAN>\n" );
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