document.write( "Question 230206: A football is kicked vertically upward from a height of 4 feet with an initial speed of 75 ft per second. What is the height of the ball 2 seconds after it was kicked from the ground. \r
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document.write( "H=4+75t-16t^2 \n" );
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Algebra.Com's Answer #170484 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! H=4+75t-16t^2, where t=2 sec \n" ); document.write( "H=4+75*2-16*2^2 \n" ); document.write( "H=4+ 150 - 16*4 \n" ); document.write( "H=4+150-64 \n" ); document.write( "H=154-64=90 feet\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or you can do it with a graphing calculator if you want to. If anyone is interested in this approach, let me know. Send me an Email at rapaljer@scc-fl.edu.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( "Seminole State College of Florida \n" ); document.write( "Altamonte Springs Campus \n" ); document.write( " |