document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230138>Question 230138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is this equation possible 0=3x^2+12x-135? And Factor it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170465 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well it is possible to factor and solve this equation.  First we can divide both sides by 3 and we will get:<br>\r<BR>\n" );
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document.write( "0 = x^2+4x-45<br>\r<BR>\n" );
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document.write( "now we need to think of numbers that multiply to -45 and add to 5.  -5 and 9 work so the equation factors to:<br>\r<BR>\n" );
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document.write( "0 = (x-5)(x+9)<br>\r<BR>\n" );
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document.write( "and to solve the equation we use the zero product property and set each factor to 0 and you will get that x = 5 and x = -9.<br> </SPAN>\n" );
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