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You can put this solution on YOUR website!
Well to do this problem we need to remember a few facts:\r
\n" ); document.write( "\n" ); document.write( "1) sec(x) = 1/cos(x)
\n" ); document.write( "2) sin^2(x) = 1-cos^2(x)
\n" ); document.write( "3) tan(x) = sin(x)/cos(x)\r
\n" ); document.write( "\n" ); document.write( "Okay now to prove this identity we need to work with one side to see if we can get the other.\r
\n" ); document.write( "\n" ); document.write( "left hand side:
\n" ); document.write( "sinxtanx
\n" ); document.write( "= sinx(sinx/cosx)by number 3.
\n" ); document.write( "= sin^2x/cosx
\n" ); document.write( "= (1-cos^2x)/cosx by number 2.
\n" ); document.write( "= 1/cosx - cos^2x/cosx
\n" ); document.write( "= secx - cosx by number 1. \r
\n" ); document.write( "\n" ); document.write( "There now we found that the left hand side equals the right hand side and we're done. Just to show you that it doesn't matter what side we choose I'm going to work with the right hand side and get the left hand side as well.\r
\n" ); document.write( "\n" ); document.write( "Right hand side:
\n" ); document.write( "secx-cosx
\n" ); document.write( "=1/cosx - cosx by 1.
\n" ); document.write( "=(1-cos^2x)/cosx
\n" ); document.write( "=sin^2x/cosx by 2.
\n" ); document.write( "=sinx/cosx * sinx
\n" ); document.write( "=tanxsinx by 3. \n" ); document.write( "