document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30370>Question 30370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in rectangle ABCD side AB= 2x+6; side BC= 5y; side CD= 7y; and side DA= 2x+2. it wants to have what x equals and what y equals. i have tried several different ways of figuring this out but i'm clueless. please help for me to understand this problem and how to do it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17046 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ASSUMING THIS IS A RECTANGLE WITH PARALLEL AND EQUAL OPOSITE SIDES THEN\r<BR>\n" );
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document.write( "7Y=2X+6 & 5Y=2X+2\r<BR>\n" );
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document.write( "Y=(2X+6)/7 SUBSTITUTING Y IN THE SECOND EQUATION WE GET <BR>\n" );
document.write( "5(2X+6)/7)=2X+2  <BR>\n" );
document.write( "(10X+30)/7=2X+2<BR>\n" );
document.write( "(10X+30)=7(2X+2)<BR>\n" );
document.write( "10X+30=14X+14<BR>\n" );
document.write( "-4X=-16<BR>\n" );
document.write( "4X=16<BR>\n" );
document.write( "X=4\r<BR>\n" );
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document.write( "7Y=2(4)+6 OR 7Y=8+6 OR 7Y=14 OR Y=2<BR>\n" );
document.write( "5Y=2(4)+2 OR 5Y=8+2 OR 5Y=10 OR Y=2\r<BR>\n" );
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document.write( "SIDES ARE 2X+6  2(4)+6 8+6=14<BR>\n" );
document.write( "          2X+2  2(4)+2 8+2=10<BR>\n" );
document.write( "          5(2)=10 & 7(2)=14<BR>\n" );
document.write( " </SPAN>\n" );
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