document.write( "Question 230087: A freight train leaves a station traveling 60 miles per hour. Thirty minutes later a passenger train leaves the station in the same direction on a parallel track at a speed of 72 miles per hour. How long will it take the passenger train to catch the freight train? \n" ); document.write( "
Algebra.Com's Answer #170448 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
In 30 min, the freight train has gone:
\n" ); document.write( "\"d+=+60%2A%281%2F2%29\" mi
\n" ); document.write( "\"d+=+30\" mi (it's headstart)
\n" ); document.write( "When the passenger train leaves the station, I start a stopwatch
\n" ); document.write( "and I'll stop it at time = \"t\" when trains meet
\n" ); document.write( "Let \"d%5Bp%5D\" = distance the passenger train has to
\n" ); document.write( "go to catch freight train
\n" ); document.write( "For passenger train:
\n" ); document.write( "(1) \"d%5Bp%5D+=+72t\"
\n" ); document.write( "For freight train:
\n" ); document.write( "(2) \"d%5Bp%5D+-+30+=+60t\"
\n" ); document.write( "Substitute (1) in (2)
\n" ); document.write( "\"72t+-+30+=+60t\"
\n" ); document.write( "\"12t+=+30\"
\n" ); document.write( "\"t+=+5%2F2\"
\n" ); document.write( "The passenger train catches the freight train in 2.5 hrs
\n" ); document.write( "check:
\n" ); document.write( "(1) \"d%5Bp%5D+=+72t\"
\n" ); document.write( "\"d%5Bp%5D+=+72%2A2.5\"
\n" ); document.write( "\"d%5Bp%5D+=+180\" mi
\n" ); document.write( "and
\n" ); document.write( "(2) \"d%5Bp%5D+-+30+=+60t\"
\n" ); document.write( "\"d%5Bp%5D+=+60%2A2.5+%2B+30\"
\n" ); document.write( "\"d%5Bp%5D+=+150+%2B+30\"
\n" ); document.write( "\"d%5Bp%5D+=+180\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" );