document.write( "Question 229988: The daily cost of photocopying in a certain office is assumed to be normally distributed with a mean of $80 and a standard deviation of $4. Find the probability that:
\n" );
document.write( "a) the cost for a randomly selected day is more than $75 -----> = 0.8944
\n" );
document.write( "b) the average cost of 10 randomly selected days is more than $75\r
\n" );
document.write( "\n" );
document.write( "Stuck with part b, should it just be 0.8944^10? \n" );
document.write( "
Algebra.Com's Answer #170414 by stanbon(75887) ![]() You can put this solution on YOUR website! The daily cost of photocopying in a certain office is assumed to be normally distributed with a mean of $80 and a standard deviation of $4. Find the probability that: \n" ); document.write( "a) the cost for a randomly selected day is more than $75 -----> = 0.8944 \n" ); document.write( "b) the average cost of 10 randomly selected days is more than $75 \n" ); document.write( "Stuck with part b, should it just be 0.8944^10? \n" ); document.write( "-------------------------- \n" ); document.write( "Comment: Part \"a\" is a population problem where the mean is u and std = sigma \n" ); document.write( "Part \"b\" is a sample-means problem where the mean of the sample means is u but std = sigma/sqrt(n) \n" ); document.write( "----------------------------- \n" ); document.write( "Part \"b\": \n" ); document.write( "z(75) = (75-80)/(4/sqrt(10)) = -3.9528 \n" ); document.write( "--- \n" ); document.write( "P(x-bar > 75) = P(z > -3.9528) = 0.9999.. \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |