document.write( "Question 30346: x+3/5= x+1/x-3 This ia a rational fraction and i cant seem to find the right answer is there anyway you could help me.! Please and thank you \n" ); document.write( "
Algebra.Com's Answer #17041 by Fermat(136)\"\" \"About 
You can put this solution on YOUR website!
x+3/5= x+1/x-3
\n" ); document.write( "There ae two ways to interpret the above eqn
\n" ); document.write( "1) x+(3/5)= x+(1/x)-3
\n" ); document.write( "2) (x+3)/5= (x+1)/(x-3)
\n" ); document.write( "You should use bracketed terms to avoid ambiguity, thanks.
\n" ); document.write( "Solution for case 1)
\n" ); document.write( "====================
\n" ); document.write( "x+(3/5)= x+(1/x)-3
\n" ); document.write( "The denominators in your fractions are x and 5, so multiply all the terms by 5x (the product of the denominators). This gives,
\n" ); document.write( "5x² + 3x = 5x² + 5 - 15x
\n" ); document.write( "18x = 5
\n" ); document.write( "x = 5/18
\n" ); document.write( "========
\n" ); document.write( "Solution for case 2)
\n" ); document.write( "====================
\n" ); document.write( "(x+3)/5= (x+1)/(x-3)
\n" ); document.write( "cross-multiply
\n" ); document.write( "(x+3)(x-3) = 5(x+1)
\n" ); document.write( "x² - 9 = 5x + 5
\n" ); document.write( "x² - 5x - 14 = 0
\n" ); document.write( "(x+2)(x-7) = 0
\n" ); document.write( "x = -2, x = 7
\n" ); document.write( "============= \n" ); document.write( "
\n" );