document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30309>Question 30309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lillian is about to invest $20,000, part at 6% and the rest at 8%.<BR>\n" );
document.write( "What is the most that she can invest at 6% and still be gauranteed at least $1500 in intrest per year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17036 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Lillian invest $P @ 6%<BR>\n" );
document.write( "Let Lillian also invest $(20,000 - P) @ 8%<BR>\n" );
document.write( "Total revenue is:<BR>\n" );
document.write( "P*6/100 + (20,000 - P)*8/100 >= 1500<BR>\n" );
document.write( "6P + 160,000 - 8P >= 150,000<BR>\n" );
document.write( "-2P >= -10,000<BR>\n" );
document.write( "2P <= 10,000<BR>\n" );
document.write( "P <= 5,000<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Thus Lillian must invest no more than $5,000 @ 6% (with the remainder @ 8%) inorder to ensure that her total revenue will exceed $1500. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );