document.write( "Question 229892: find the inverse of f(x)= 1/3x^3+1 is it one-to-one, why or why not? \n" ); document.write( "
Algebra.Com's Answer #170345 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the inverse of f(x)= (1/3)x^3+1 is it one-to-one, why or why not? \n" ); document.write( "--------------- \n" ); document.write( "Inverse: \n" ); document.write( "Interchange x and y to get: \n" ); document.write( "x = (1/3)y^3 + 1 \n" ); document.write( "(1/3)y^3 = x-1 \n" ); document.write( "y^3 = 3(x-1) \n" ); document.write( "y = [3x-3]^(1/3) \n" ); document.write( "-------------------------- \n" ); document.write( "One-to-One? \n" ); document.write( "Graph to see: \n" ); document.write( " \n" ); document.write( "=================================================== \n" ); document.write( "f passes the vertical line test and the horizontal line test \n" ); document.write( "so it is one-to-one \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |