document.write( "Question 229892: find the inverse of f(x)= 1/3x^3+1 is it one-to-one, why or why not? \n" ); document.write( "
Algebra.Com's Answer #170345 by stanbon(75887)\"\" \"About 
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find the inverse of f(x)= (1/3)x^3+1 is it one-to-one, why or why not?
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\n" ); document.write( "Inverse:
\n" ); document.write( "Interchange x and y to get:
\n" ); document.write( "x = (1/3)y^3 + 1
\n" ); document.write( "(1/3)y^3 = x-1
\n" ); document.write( "y^3 = 3(x-1)
\n" ); document.write( "y = [3x-3]^(1/3)
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\n" ); document.write( "One-to-One?
\n" ); document.write( "Graph to see:
\n" ); document.write( "\"graph%28400%2C300%2C-20%2C20%2C-4%2C4%2C%281%2F3%29x%5E3+%2B+1%29\"
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\n" ); document.write( "f passes the vertical line test and the horizontal line test
\n" ); document.write( "so it is one-to-one
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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