document.write( "Question 229763: Find the center and radius of the circle given by the equation x^2 + y^2 - 8x + 2y - 11 = 0 \n" ); document.write( "
Algebra.Com's Answer #170264 by nerdybill(7384)\"\" \"About 
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x^2 + y^2 - 8x + 2y - 11 = 0
\n" ); document.write( "x^2 + y^2 - 8x + 2y = 11
\n" ); document.write( "Group x's and y's:
\n" ); document.write( "(x^2 - 8x) + (y^2 + 2y) = 11
\n" ); document.write( "Complete the square:
\n" ); document.write( "(x^2 - 8x + __ ) + (y^2 + 2y + __) = 11
\n" ); document.write( "(x^2 - 8x + 16 ) + (y^2 + 2y + 1) = 11 + 16 + 1
\n" ); document.write( "(x - 4 )^2 + (y + 1)^2 = 28
\n" ); document.write( "(x - 4 )^2 + (y - -1)^2 = 28
\n" ); document.write( "Center: (h,k) = (4, -1)
\n" ); document.write( "radius: sqrt(28) = 2sqrt(7)
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