document.write( "Question 229539: An area of 52 square feet is to be enclosed by two squares whose sides are in the ratio of 2:3.Find the sides of the two squares. \n" ); document.write( "
Algebra.Com's Answer #170242 by ankor@dixie-net.com(22740)\"\" \"About 
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An area of 52 square feet is to be enclosed by two squares whose sides are in the ratio of 2:3.
\n" ); document.write( "Find the sides of the two squares.
\n" ); document.write( ":
\n" ); document.write( "Let x = side of one square
\n" ); document.write( "Let y = side of the other squares
\n" ); document.write( "then
\n" ); document.write( "\"x%2Fy\" = \"2%2F3\"
\n" ); document.write( "therefore
\n" ); document.write( "2y = 3x
\n" ); document.write( "y = \"3%2F2\"x
\n" ); document.write( "y = 1.5x
\n" ); document.write( ":
\n" ); document.write( "Area of the two squares:
\n" ); document.write( "x^2 + y^2 = 52
\n" ); document.write( "Replace y with 1.5x
\n" ); document.write( "x^2 + (1.5x)^2 = 52
\n" ); document.write( "x^2 + 2.25x^2 = 52
\n" ); document.write( "3.25x^2 = 52
\n" ); document.write( "x^2 = \"52%2F3.25\"
\n" ); document.write( "x^2 = 16
\n" ); document.write( "x = \"sqrt%2816%29\"
\n" ); document.write( "x = 4 ft side of one square
\n" ); document.write( "and
\n" ); document.write( "y = 1.5(4)
\n" ); document.write( "y = 6 ft side of the other square
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution: 4^2 + 6^2 = 52
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