document.write( "Question 229672: twice the difference of the number and 8 is equal to three times the sum of the number and 3. find the number.\r
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document.write( "2(x-8)=3x+3
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document.write( "2x-16=3x+3
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document.write( "2x-16-2=3x+3-2
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document.write( "2x+14=3x+1
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document.write( "16/2=4/2
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document.write( "8/2=4
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document.write( "x=4 \n" );
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Algebra.Com's Answer #170224 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! You just forgot the parentheses on the right side! Also, I'm not sure why in the third step you subtracted 2 from each side.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(x-8)=3(x+3) \n" ); document.write( "2x-16=3x+9 \n" ); document.write( "2x-16+16=3x+9+16 \n" ); document.write( "2x=3x+25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 3x from each side: \n" ); document.write( "2x-3x=3x-3x-7 \n" ); document.write( "-x=25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by -1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "Twice the difference of the number and 8 is equal to three times the sum of the number and 3. \r \n" ); document.write( "\n" ); document.write( "2*(-25-8)=3(-25+3) \n" ); document.write( "2*-33=3*-22 \n" ); document.write( "-66=-66\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It checks!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje \n" ); document.write( " |