document.write( "Question 229599: Factor the trinomial.\r
\n" ); document.write( "\n" ); document.write( "b^3-2b^2-63b
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Algebra.Com's Answer #170201 by Earlsdon(6294)\"\" \"About 
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Factor:
\n" ); document.write( "\"b%5E3-2b%5E2-63b\" First, since each term has common factor of b, a b can be factored.
\n" ); document.write( "\"b%28b%5E2-2b-63%29\"
\n" ); document.write( "Now look at the constant term (-63) and see what its factors are:
\n" ); document.write( "\"-63+=+3%28-21%29\"
\n" ); document.write( "\"-63+=+-3%2821%29\"
\n" ); document.write( "\"-63+=+7%28-9%29\"
\n" ); document.write( "\"-63+=+-7%289%29\"
\n" ); document.write( "Now you need the pair of factors from the above list whose sum is -2 (the coefficient of the center term of the trinomial.
\n" ); document.write( "A quick look will show that the pair that meets this requirement is \"7%28-9%29\" because \"7%2B%28-9%29+=+-2\". Now you can finish the factoring process.
\n" ); document.write( "\"highlight%28b%5E3-2b%5E2-63b+=+b%28b%2B7%29%28b-9%29%29\"
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