document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229589>Question 229589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> assume that the perimeter of a pentagon whose perimeter is 4a+4 is three times the perimeter of a triangle whose perimeter is a+3.\r<BR>\n" );
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document.write( "a.)find a\r<BR>\n" );
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document.write( "b.)using your answer to 22A, calculate the perimeters of both the pentagon and the triangle.(if youve done your calculations correctly, the pentagons perimeter will be 3 times the perimeter of the triangle.)\r<BR>\n" );
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document.write( "c.)an octagon has the same perimeter as the pentagon you calculated in problem 22b. what is the length of each side of the octagon?\r<BR>\n" );
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document.write( "please please please help me i need help im desperate!!!!!!!!!!!!!!!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> assume that the perimeter of a pentagon whose perimeter is 4a+4 is three times the perimeter of a triangle whose perimeter is a+3. <BR>\n" );
document.write( "a.)find a <BR>\n" );
document.write( "(4a+4)= 3(a+3)<BR>\n" );
document.write( "4a+4 = 3a+9<BR>\n" );
document.write( "a = 5<BR>\n" );
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document.write( "b.)using your answer to 22A, calculate the perimeters of both the pentagon and the triangle.(if youve done your calculations correctly, the pentagons perimeter will be 3 times the perimeter of the triangle.)<BR>\n" );
document.write( "perimeter of pentagon = 4*5+4 = 24<BR>\n" );
document.write( "perimeter of triangle = 5+3 = 8<BR>\n" );
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document.write( "c.)an octagon has the same perimeter as the pentagon you calculated in problem 22b. what is the length of each side of the octagon? <BR>\n" );
document.write( "8s = 24<BR>\n" );
document.write( "s = 3 (each side is 3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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