document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229313>Question 229313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i solve 1/2v= -1/2v + 3/8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170155 by </B><A HREF=/tutors/aboutme.mpl?userid=shymeerab><B>shymeerab(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shymeerab><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2v= -1/2v + 3/8<BR>\n" );
document.write( "1/2v+1/2v=3/8<BR>\n" );
document.write( "2/2v=3/8<BR>\n" );
document.write( "1/v=3/8<BR>\n" );
document.write( "v=8/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );