document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229387>Question 229387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carrie walks at 3mph<BR>\n" );
document.write( "Crystal rides bike at 9mph\r<BR>\n" );
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document.write( "carrie takes 20 minutes longer than Crystal to get to school.<BR>\n" );
document.write( "They live the same distance from school.<BR>\n" );
document.write( "What is the distance to school?\r<BR>\n" );
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document.write( "This is what I have, not making sense?<BR>\n" );
document.write( "d=rxt<BR>\n" );
document.write( "d= 3 x (t + 20)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170151 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you know the rates<BR>\n" );
document.write( "the distances are equal<BR>\n" );
document.write( "solve for the time and then substitute to find the distance<BR>\n" );
document.write( "(remember:  20 min is 1/3 hr)\r<BR>\n" );
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document.write( "3(t + 1/3) = 9 (t) ___ 3t + 1 = 9t ___ 1 = 6t ___ 1/6 = t\r<BR>\n" );
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document.write( "substituting ___ d = 9(1/6) = 9/6 = 1.5 mi </SPAN>\n" );
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