document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229501>Question 229501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show an equation and a solution. How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170142 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12 * .4 = 4.8<BR>\n" );
document.write( " x * 1.0 = x<BR>\n" );
document.write( "(x+12)*.6=4.8x<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".6x+7.2=4.8x<BR>\n" );
document.write( "-4.2x=-7.2<BR>\n" );
document.write( "x=7.2/4.2<BR>\n" );
document.write( "=12/7 L<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );