document.write( "Question 30362: Question: Find the equation of the ellipse whose center is (5,-3) that has a vertex at 13,-3) and a minor axis of lenght 10.\r
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document.write( "POssible Answers:
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document.write( "(A) (x-5)^2/64 + (y+3)^2/25 = 1\r
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document.write( "(B) (x+5)^2/64 + (y-3)^2/25 = 1\r
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document.write( "(C) x^2/64 + y^2/25 = 1\r
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document.write( "(D) none of these \n" );
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Algebra.Com's Answer #17014 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING AND TRY..IF STILL IN DIFFICULTY PLEASE COME BACK... \n" ); document.write( "OK I WORKED IT OUT FOR YOU NOW\r \n" ); document.write( "\n" ); document.write( "I TOLD YOU EQN IS \n" ); document.write( "(X-H)^2/A^2 + (Y-K)^2/B^2.... \n" ); document.write( "WHERE H,K IS CENTRE...SO H=5 AND K=-3 AS CENTRE IS GIVEN AS (5,-3)....NOW VERTEX IS (13,-3)...IT LIES ON ELLIPSE..SO IT SATISFIES THE EQN \n" ); document.write( "(13-5)^2/A^2 +(-3+3)^2/B^2 =1 \n" ); document.write( "HENCE A^2=64...OR A=8 \n" ); document.write( "MINOR AXIS =10=2B...HENCE B=5..SO EQN.S \n" ); document.write( "(X-H)^2/64 + (Y+3)^2/25 =1 \n" ); document.write( "THAT IS A IS CORRECT.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you help me write an equation for an ellipse with a major axis with endpoints of (0,8), and (0,-8) with foci of (0,5) and (0,-5)?\r \n" ); document.write( "\n" ); document.write( "1 solutions\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------- \n" ); document.write( "Answer 16810 by venugopalramana(1120) on 2006-03-13 11:19:12 (Show Source): \r \n" ); document.write( "\n" ); document.write( "Can you help me write an equation for an ellipse with a major axis with endpoints of (0,8), and (0,-8) with foci of (0,5) and (0,-5)? \n" ); document.write( "THIS SHOWS THAT X AXIS IS THE MAJOR AXIS \n" ); document.write( "STANDARD EQN.OF ELLIPSE IS \n" ); document.write( "(X-H)^2/A^2 +(Y-K)^2/B^2=1 \n" ); document.write( "CENTRE IS (H,K)..AS PER THE PROBLEM H=K=0 AS CENTRE OF ELLIPSE IS AT (0,0)..SINCE major axis with endpoints ARE (0,8), and (0,-8) \n" ); document.write( "WHERE MAJOR AXIS =2A=8+8=16...SO A=8..SINCE major axis with endpoints ARE (0,8), and (0,-8) \n" ); document.write( "FOCI ARE GIVEN BY \n" ); document.write( "AE,0 AND -AE,0...SO AE =5...SO E=5/A=5/8 \n" ); document.write( "BUT E=SQRT{(A^2-B^2)/A^2}=5/8...SQUARING \n" ); document.write( "25/64=(A^2-B^2)/A^2=1-B^2/A^2 \n" ); document.write( "B^2/64=1-25/64=49/64 \n" ); document.write( "B^2=49 \n" ); document.write( "B=7 \n" ); document.write( "HENCE EQN. OF ELLIPSE IS \n" ); document.write( "X^2/64 + Y^2/49 = 1 \n" ); document.write( " |