document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30357>Question 30357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use Descartes rule of signs to determine how many positive and how many negative real zeros that polynomial functions may have. Do not attmept to find the zeros.<BR>\n" );
document.write( "f(x) =x^6-2x^5+4x^4+4x^3+5x^2=5x+3\r<BR>\n" );
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document.write( "(a) 5, 3, or 1 positive real zero; 2 or no negative real zeros<BR>\n" );
document.write( "(b)4,2, or no positive real zeros; 2 or no negative real zeros<BR>\n" );
document.write( "(c)2 or no positive real zeros; 4, 2, or no negatitive real zeros<BR>\n" );
document.write( "(d) 4, 2, or no positive real zeros; 3 or 1 negative real zero </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17012 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = x^6 - 2x^5 + 4x^4 + 4x^3 + 5x^2 - 5x + 3\r<BR>\n" );
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document.write( "Number of variations in sign is four<BR>\n" );
document.write( "=> Number of positive real zeros is 4, 2, or none\r<BR>\n" );
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document.write( "f(-x) =  x^6 + 2x^5 + 4x^4 - 4x^3 + 5x^2 + 5x - 3<BR>\n" );
document.write( "Number of variations in sign is three <BR>\n" );
document.write( "=> Number of negative real zeros is 3 or 1 \r<BR>\n" );
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document.write( "The correct answer would be d (4, 2, or no positive real zeros; 3 or 1 negative real zero)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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