document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229401>Question 229401</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ancient greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the lengthto the width was approximatly 8 to 5, the golden ratio.  the length of a rectangular painting is 2 ft longer than its width, then for what dimentions would the length and width have the golden rule? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170119 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8/5=(X+2)/X<BR>\n" );
document.write( "5(X+2)=8X<BR>\n" );
document.write( "5X+10=8X<BR>\n" );
document.write( "5X-8X=-10<BR>\n" );
document.write( "-3X=-10<BR>\n" );
document.write( "X=-10/-3<BR>\n" );
document.write( "X=3.33 FT. FOR THE WIDTH.<BR>\n" );
document.write( "3.33+2=5.33 FT. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "8/5=5.33/3.33<BR>\n" );
document.write( "8*3.33=5*5.33<BR>\n" );
document.write( "26.64~26.65<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );