document.write( "Question 229415: 11b/6=b-5
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Algebra.Com's Answer #170093 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
\"11b%2F6=b-5\"\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Multiply by 6 to both sides of the equation to get rid of the denominator\r
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\n" ); document.write( "\n" ); document.write( "\"11b%2Across%286%29%2Fcross%286%29=6b-6%2A5\"\r
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\n" ); document.write( "\n" ); document.write( "\"11b=6b-30\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Subtract 6b from both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"11b-6b=cross%286b%29-30-cross%286b%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"5b=-30\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Divide by 5 to both sides to solve for b\r
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\n" ); document.write( "\n" ); document.write( "\"cross%285%29b%2Fcross%285%29=-30%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=-6\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Check and substitute \"b=-6\" into original equation \"11b%2F6=b-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"11%2A%28-6%29%2F6=-6-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"-11=-11\" which is a true statement\r
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\n" ); document.write( "\n" ); document.write( "Step 5. ANSWER: Solution is \"b=-6\"\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
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