document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229364>Question 229364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> measure of angle 1 is (2x-3y) and measure of angle 2 is (x+3y) what does x and y =? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170071 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF these are complementary angles then:<BR>\n" );
document.write( "(2x-3y)+(x+3y)=90<BR>\n" );
document.write( "2x+x=90<BR>\n" );
document.write( "3x=90<BR>\n" );
document.write( "x=90/3<BR>\n" );
document.write( "x=30 degrees.<BR>\n" );
document.write( "y=0 degrees.<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "IF they are suplementary angles then:<BR>\n" );
document.write( "(2x-3y)+(+x+3y)=180<BR>\n" );
document.write( "3x=180<BR>\n" );
document.write( "x=180/3<BR>\n" );
document.write( "x=60 degrees.<BR>\n" );
document.write( "y=0 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );