document.write( "Question 229286: graph 30x+50y-100=0
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Algebra.Com's Answer #170033 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
graph \r
\n" ); document.write( "\n" ); document.write( "30x+50y-100=0 or 30x+50y=100
\n" ); document.write( "3x-15y-30=0 or 3x-15y=30\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The graph of the two lines are shown below:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C+-10%2C+10%2C+-10%2C+10%2C+-3x%2F5%2B2%2C+x%2F5-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. The intersection point is (-1,5) or x=-1 and y=5\r
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\n" ); document.write( "\n" ); document.write( "Step 3. As a check, solve using substitution\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++30%5Cx+%2B+50%5Cy+=+100%2C%0D%0A++++3%5Cx+%2B+-15%5Cy+=+30+%29%0D%0A++\"We'll use substitution. After moving 50*y to the right, we get:
\n" ); document.write( " \"30%2Ax+=+100+-+50%2Ay\", or \"x+=+100%2F30+-+50%2Ay%2F30\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"3%2A%28100%2F30+-+50%2Ay%2F30%29+%2B+-15%5Cy+=+30\" and simplify: So, we know that y=-1. Since \"x+=+100%2F30+-+50%2Ay%2F30\", x=5.
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\n" ); document.write( " Answer: \"system%28+x=5%2C+y=-1+%29\".
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\n" ); document.write( "\n" ); document.write( "which yields the same result with x=5 and y=-1.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV
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