document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=229250>Question 229250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of 75% gas and 90% gas would you need for 1200 liters of 85% gas? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #169994 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=169994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .90x+.75(1,200-x)=.85*1,200<BR>\n" );
document.write( ".90x+900-.75x=1,020<BR>\n" );
document.write( ".15x=1,020-900<BR>\n" );
document.write( ".15x=120<BR>\n" );
document.write( "x=120/.15<BR>\n" );
document.write( "x=800 liters of 90% gas is used.<BR>\n" );
document.write( "1,200-800=400 liters of 75% gas is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".90*800+.75*400=1,020<BR>\n" );
document.write( "720+300=1,020<BR>\n" );
document.write( "1,020=1,020   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );